tests/test-rust-revlog.py
author Pierre-Yves David <pierre-yves.david@octobus.net>
Fri, 15 Mar 2024 01:31:57 +0100
branchstable
changeset 51505 c9ceb4f60256
parent 51254 f94c10334bcb
permissions -rw-r--r--
phases: avoid N² behavior in `advanceboundary` We allowed duplicated entries in the deque, which each entry could potentially insert all its ancestors. So advancing boundary for the full repository would mean each revision would walk all its ancestors, resulting in O(N²) iteration. For repository of any decent size, N² is quickly insane. We introduce a simple set to avoid this and get back to reasonable performance.

import struct
import unittest

from mercurial.node import hex

try:
    from mercurial import rustext

    rustext.__name__  # trigger immediate actual import
except ImportError:
    rustext = None
else:
    from mercurial.rustext import revlog

    # this would fail already without appropriate ancestor.__package__
    from mercurial.rustext.ancestor import LazyAncestors

from mercurial.testing import revlog as revlogtesting

header = struct.unpack(">I", revlogtesting.data_non_inlined[:4])[0]


@unittest.skipIf(
    rustext is None,
    "rustext module revlog relies on is not available",
)
class RustRevlogIndexTest(revlogtesting.RevlogBasedTestBase):
    def test_heads(self):
        idx = self.parseindex()
        rustidx = revlog.Index(revlogtesting.data_non_inlined, header)
        self.assertEqual(rustidx.headrevs(), idx.headrevs())

    def test_len(self):
        idx = self.parseindex()
        rustidx = revlog.Index(revlogtesting.data_non_inlined, header)
        self.assertEqual(len(rustidx), len(idx))

    def test_ancestors(self):
        rustidx = revlog.Index(revlogtesting.data_non_inlined, header)
        lazy = LazyAncestors(rustidx, [3], 0, True)
        # we have two more references to the index:
        # - in its inner iterator for __contains__ and __bool__
        # - in the LazyAncestors instance itself (to spawn new iterators)
        self.assertTrue(2 in lazy)
        self.assertTrue(bool(lazy))
        self.assertEqual(list(lazy), [3, 2, 1, 0])
        # a second time to validate that we spawn new iterators
        self.assertEqual(list(lazy), [3, 2, 1, 0])

        # let's check bool for an empty one
        self.assertFalse(LazyAncestors(rustidx, [0], 0, False))


@unittest.skipIf(
    rustext is None,
    "rustext module revlog relies on is not available",
)
class RustRevlogNodeTreeClassTest(revlogtesting.RustRevlogBasedTestBase):
    def test_standalone_nodetree(self):
        idx = self.parserustindex()
        nt = revlog.NodeTree(idx)
        for i in range(4):
            nt.insert(i)

        bin_nodes = [entry[7] for entry in idx]
        hex_nodes = [hex(n) for n in bin_nodes]

        for i, node in enumerate(hex_nodes):
            self.assertEqual(nt.prefix_rev_lookup(node), i)
            self.assertEqual(nt.prefix_rev_lookup(node[:5]), i)

        # all 4 revisions in idx (standard data set) have different
        # first nybbles in their Node IDs,
        # hence `nt.shortest()` should return 1 for them, except when
        # the leading nybble is 0 (ambiguity with NULL_NODE)
        for i, (bin_node, hex_node) in enumerate(zip(bin_nodes, hex_nodes)):
            shortest = nt.shortest(bin_node)
            expected = 2 if hex_node[0] == ord('0') else 1
            self.assertEqual(shortest, expected)
            self.assertEqual(nt.prefix_rev_lookup(hex_node[:shortest]), i)

        # test invalidation (generation poisoning) detection
        del idx[3]
        self.assertTrue(nt.is_invalidated())


if __name__ == '__main__':
    import silenttestrunner

    silenttestrunner.main(__name__)