bundle-spec: properly identify changegroup-less bundle
It is possible to produce a bundle without changegroup. For example if we want
to only send phases or obsolescence information. However that lead to crash for
command that identifies bundle content. So we fix that.
The test will come in the next changesets, when we fix another bug preventing to
generate such bundle by hand.
import os
from mercurial import (
hg,
merge,
ui as uimod,
)
u = uimod.ui.load()
repo = hg.repository(u, b'test1', create=1)
os.chdir('test1')
def commit(text, time):
repo.commit(text=text, date=b"%d 0" % time)
def addcommit(name, time):
f = open(name, 'wb')
f.write(b'%s\n' % name)
f.close()
with repo.wlock():
with repo.dirstate.changing_files(repo):
repo[None].add([name])
commit(name, time)
def update(rev):
merge.clean_update(repo[rev])
def merge_(rev):
merge.merge(repo[rev])
if __name__ == '__main__':
addcommit(b"A", 0)
addcommit(b"B", 1)
update(0)
addcommit(b"C", 2)
merge_(1)
commit(b"D", 3)
update(2)
addcommit(b"E", 4)
addcommit(b"F", 5)
update(3)
addcommit(b"G", 6)
merge_(5)
commit(b"H", 7)
update(5)
addcommit(b"I", 8)
# Ancestors
print('Ancestors of 5')
for r in repo.changelog.ancestors([5]):
print(r, end=' ')
print('\nAncestors of 6 and 5')
for r in repo.changelog.ancestors([6, 5]):
print(r, end=' ')
print('\nAncestors of 5 and 4')
for r in repo.changelog.ancestors([5, 4]):
print(r, end=' ')
print('\nAncestors of 7, stop at 6')
for r in repo.changelog.ancestors([7], 6):
print(r, end=' ')
print('\nAncestors of 7, including revs')
for r in repo.changelog.ancestors([7], inclusive=True):
print(r, end=' ')
print('\nAncestors of 7, 5 and 3, including revs')
for r in repo.changelog.ancestors([7, 5, 3], inclusive=True):
print(r, end=' ')
# Descendants
print('\n\nDescendants of 5')
for r in repo.changelog.descendants([5]):
print(r, end=' ')
print('\nDescendants of 5 and 3')
for r in repo.changelog.descendants([5, 3]):
print(r, end=' ')
print('\nDescendants of 5 and 4')
print(*repo.changelog.descendants([5, 4]), sep=' ')