bundle-spec: properly identify changegroup-less bundle
It is possible to produce a bundle without changegroup. For example if we want
to only send phases or obsolescence information. However that lead to crash for
command that identifies bundle content. So we fix that.
The test will come in the next changesets, when we fix another bug preventing to
generate such bundle by hand.
import os
import sys
from mercurial import dispatch
def printb(data, end=b'\n'):
out = getattr(sys.stdout, 'buffer', sys.stdout)
out.write(data + end)
out.flush()
def testdispatch(cmd):
"""Simple wrapper around dispatch.dispatch()
Prints command and result value, but does not handle quoting.
"""
printb(b"running: %s" % (cmd,))
req = dispatch.request(cmd.split())
result = dispatch.dispatch(req)
printb(b"result: %r" % (result,))
testdispatch(b"init test1")
os.chdir('test1')
# create file 'foo', add and commit
f = open('foo', 'wb')
f.write(b'foo\n')
f.close()
testdispatch(b"add foo")
testdispatch(b"commit -m commit1 -d 2000-01-01 foo")
# append to file 'foo' and commit
f = open('foo', 'ab')
f.write(b'bar\n')
f.close()
testdispatch(b"commit -m commit2 -d 2000-01-02 foo")
# check 88803a69b24 (fancyopts modified command table)
testdispatch(b"log -r 0")
testdispatch(b"log -r tip")