strip: don't use "full" and "partial" to describe bundles
The partial bundle is not a subset of the full bundle, and the full
bundle is not full in any way that i see. The most obvious
interpretation of "full" I can think of is that it has all commits
back to the null revision, but that is not what the "full" bundle
is. The "full" bundle is simply a backup of what the user asked us to
strip (unless --no-backup). The "partial" bundle contains the
revisions we temporarily stripped because they had higher revision
numbers that some commit that the user asked us to strip.
The "full" bundle is already called "backup" in the code, so let's use
that in user-facing messages too. Let's call the "partial" bundle
"temporary" in the code.
Source bundle was generated with the following script:
# hg init
# echo a > a
# ln -s a l
# hg ci -Ama -d'0 0'
# mkdir b
# echo a > b/a
# chmod +x b/a
# hg ci -Amb -d'1 0'
$ hg init
$ hg -q pull "$TESTDIR/bundles/test-manifest.hg"
The next call is expected to return nothing:
$ hg manifest
$ hg co
3 files updated, 0 files merged, 0 files removed, 0 files unresolved
$ hg manifest
a
b/a
l
$ hg files -vr .
2 a
2 x b/a (glob)
1 l l
$ hg files -r . -X b
a
l
$ hg manifest -v
644 a
755 * b/a
644 @ l
$ hg manifest --debug
b789fdd96dc2f3bd229c1dd8eedf0fc60e2b68e3 644 a
b789fdd96dc2f3bd229c1dd8eedf0fc60e2b68e3 755 * b/a
047b75c6d7a3ef6a2243bd0e99f94f6ea6683597 644 @ l
$ hg manifest -r 0
a
l
$ hg manifest -r 1
a
b/a
l
$ hg manifest -r tip
a
b/a
l
$ hg manifest tip
a
b/a
l
$ hg manifest --all
a
b/a
l
The next two calls are expected to abort:
$ hg manifest -r 2
abort: unknown revision '2'!
[255]
$ hg manifest -r tip tip
abort: please specify just one revision
[255]