merge: introduce new format for the state file
This new format will allow us to address common bugs while doing special merge
(graft, backout, rebase…) and record user choice during conflict resolution.
The format is open so we can add more record for future usage.
This file still store hexified version of node to help human willing to debug
it by hand. The overhead or oversize are not expected be an issue.
The old format is still used. It will be written to disk along side the newer
format. And at parse time we detect if the data from old version of the
mergestate are different from the one in the new version file. If its the same,
both have most likely be written at the same time and you can trust the extra
data from the new file. If it differs, the old file have been written by an
older version of mercurial that did not knew about the new file. In that case we
use the content of the old file.
# dicthelpers.py - helper routines for Python dicts
#
# Copyright 2013 Facebook
#
# This software may be used and distributed according to the terms of the
# GNU General Public License version 2 or any later version.
def diff(d1, d2, default=None):
'''Return all key-value pairs that are different between d1 and d2.
This includes keys that are present in one dict but not the other, and
keys whose values are different. The return value is a dict with values
being pairs of values from d1 and d2 respectively, and missing values
treated as default, so if a value is missing from one dict and the same as
default in the other, it will not be returned.'''
res = {}
if d1 is d2:
# same dict, so diff is empty
return res
for k1, v1 in d1.iteritems():
v2 = d2.get(k1, default)
if v1 != v2:
res[k1] = (v1, v2)
for k2 in d2:
if k2 not in d1:
v2 = d2[k2]
if v2 != default:
res[k2] = (default, v2)
return res
def join(d1, d2, default=None):
'''Return all key-value pairs from both d1 and d2.
This is akin to an outer join in relational algebra. The return value is a
dict with values being pairs of values from d1 and d2 respectively, and
missing values represented as default.'''
res = {}
for k1, v1 in d1.iteritems():
if k1 in d2:
res[k1] = (v1, d2[k1])
else:
res[k1] = (v1, default)
if d1 is d2:
return res
for k2 in d2:
if k2 not in d1:
res[k2] = (default, d2[k2])
return res